\(1*3*7=21\)
\(21*5=105\)
\(105*9=945\) is close to \(10^3\)
answer is
ACarcass wrote:
The product of the first five positive odd integers is closest to which of the following powers of 10?
(A) \(10^3\)
(B) \(10^4\)
(C) \(10^5\)
(D) \(10^6\)
(E) \(10^7\)
Kudos for the right answer and explanation
Question part of the project GRE Quant/Math Extreme Challenge Daily (2021) EditionGRE - Math Book