Re: A vehicle leaves City A at 9 a.m., moving at an average speed of 50 mi
[#permalink]
02 Sep 2021, 20:02
A vehicle leaves City A at 9 a.m., moving at an average speed of 50 miles per hour, and without making any stops arrives at City B at 2 p.m.
Total time taken = \(5\) hours @ \(50\)mph
Total distance \(= 250\) miles
If the speed \(= 65\) mph
Time = \(\frac{distance}{speed} = \frac{250}{65} = 3.84hours\)
\(3\) hours & \(51\)mins
The vehicle will be at City B at \(12:51\)pm
Answer B