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If k is a multiple of 3 and k = (m2 )n, where m and n are prime number
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04 Sep 2021, 07:55
If k is a multiple of 3 and \(k = (m^2)n\) then \((m^2)n\) will also be a multiple of 3
Since both m and n are prime numbers, so either m is 3 or n is 3 or both are 3
In any case, m*n will be a multiple of 3
=> \((mn)^2\) will be a multiple of \(3^2\) or 9
So, \(Answer will be E\)
Hope it helps!