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Cylinderical cans with height 6cm and radius 3cm are to be packed
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03 Sep 2021, 09:36
03 Sep 2021, 09:36
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Question Stats:
39% (02:26) correct
60% (01:45) wrong based on 48 sessions
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Cylindrical cans each with height 6cm and radius 3cm are to be packed inside a box having interior dimensions as 12cm × 18cm × 20cm
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given[/m]
Quantity A |
Quantity B |
Maximum number of cans that can be packed inside this box |
25 |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given[/m]
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
WE:Education (Education)
Cylinderical cans with height 6cm and radius 3cm are to be packed
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06 Sep 2021, 07:20
06 Sep 2021, 07:20
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Explanation:
Since, we need to maximize the number of cans - Let us assume length of the box to be 20cm, width as 18cm and height 12 cm
Now, we can either lay the cylinders or make them stand upright
So, Length wise we can put \(\frac{20}{6} = 3\) cylinders
Width wise we can put \(\frac{18}{6} = 3\) cylinders, and
we can stack two cans Height wise
Col. A: (3)(3)(2) = 18
Col. B: 25
Hence, option B
Since, we need to maximize the number of cans - Let us assume length of the box to be 20cm, width as 18cm and height 12 cm
Now, we can either lay the cylinders or make them stand upright
So, Length wise we can put \(\frac{20}{6} = 3\) cylinders
Width wise we can put \(\frac{18}{6} = 3\) cylinders, and
we can stack two cans Height wise
Col. A: (3)(3)(2) = 18
Col. B: 25
Hence, option B
General Discussion
Retired Moderator
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Posts: 326
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GRE 1: Q160 V152
Re: Cylinderical cans with height 6cm and radius 3cm are to be packed
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03 Sep 2021, 15:13
03 Sep 2021, 15:13
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Let's posit each cylinderical can as small box having sides as following:l/w/h=6/6/6 (here, l=w=r*2=3*2). Now it looks like we have a cube, and solution will be much easier if we consider the volume of a large box fitting small boxes mentioned with volume unit dimensions of 6^3. Volume of large box divided by 6^3 is 12*18*20/6^3=20. IMO, answer is B
Note: realizing that box/container fitting questions should not be solved via volume - this is not correct, I am still using the shortcut, as the indication of cube exists here..
Note: realizing that box/container fitting questions should not be solved via volume - this is not correct, I am still using the shortcut, as the indication of cube exists here..
KarunMendiratta wrote:
Cylinderical cans each with height 6cm and radius 3cm are to be packed inside a box having interior dimensions as 12cm × 18cm × 20cm
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given[/m]
Quantity A |
Quantity B |
Maximum number of cans that can be packed inside this box |
25 |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given[/m]
