edited:Let men = \(M\) and women = \(W\), then the least number of homeowners is defined as the minimum of \(M/5+W/4\), where \(M+W=200\).
The denominator of \(20\) in \(\frac{4M+5W}{20}\) implies that for every 20 club members there can be either 5 men or 4 women owning homes. Thus, for 200 club members, the least number of homeowners would be
5 women out of 20 club members and \(180/5=36\) men as the total minimum required equal to 41.
Quantity A: 41
Quantity B: 41
answer is
C KarunMendiratta wrote:
In a 200 member club consisting of men and women, exactly 20% of men and exactly 25 % women are homeowners.
Quantity A |
Quantity B |
Least number of members who are homeowners |
41 |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given