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Adam who is jogging at a constant speed of 5 miles per hour is passed
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13 Sep 2021, 21:56
13 Sep 2021, 21:56
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Question Stats:
61% (02:19) correct
38% (01:51) wrong based on 21 sessions
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Adam who is jogging at a constant speed of 5 miles per hour is passed by a cyclist traveling in the same direction along the same path at a constant speed of 18 miles per hour. The cyclist stops to wait for Adam 2 minutes after passing him, while Adam continues to walk at his constant rate.
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Quantity A |
Quantity B |
Time required by Adam to catch up with the cyclist |
5 min. |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Re: Adam who is jogging at a constant speed of 5 miles per hour is passed
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14 Sep 2021, 06:25
14 Sep 2021, 06:25
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To solve, first find out how far the Cyclist would have traveled in 2 mins before stopping, which would be 18 * 2/60 = 0.6 miles.
Next how long it will take for Adam to cover 0.6 miles at 5 miles / 60 min = 7.2 mins.
So A is larger.
Next how long it will take for Adam to cover 0.6 miles at 5 miles / 60 min = 7.2 mins.
So A is larger.
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
WE:Education (Education)
Re: Adam who is jogging at a constant speed of 5 miles per hour is passed
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14 Sep 2021, 21:01
14 Sep 2021, 21:01
eskay1981 wrote:
To solve, first find out how far the Cyclist would have traveled in 2 mins before stopping, which would be 18 * 2/60 = 0.6 miles.
Next how long it will take for Adam to cover 0.6 miles at 5 miles / 60 min = 7.2 mins.
So A is larger.
Next how long it will take for Adam to cover 0.6 miles at 5 miles / 60 min = 7.2 mins.
So A is larger.
Dear eskay1981
You are missing out a point here that even Adam kept jogging, he did not stop for those 2 minutes.
