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Re: How many gallons of a 7% saline solution must be added to 4 gallons of
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15 Sep 2021, 10:00
1
Carcass wrote:
How many gallons of a 7% saline solution must be added to 4 gallons of a 25% saline solution so that the resulting mixture is a 15% saline solution?
A. 1 B. 4 C. 5 D. 9 E. 10
This question nicely illustrates how the GRE test-makers reward students for taking their understanding of a concept to use some number sense (rather than follow a formula).
We have 4 gallons of a 25% saline solution to start
First recognize that, IF we were to add an EQUAL volume of 7% saline solution to the 4 gallons of 25% saline solution, then the salinity of the resulting mixture would be the AVERAGE of the two solutions. That is, if we add 4 gallons of 7% saline solution to the 4 gallons of 25% saline solution, the resulting solution will be 16% saline, since (7% + 25%)/2 = 16%. This 16% solution is VERY CLOSE to our goal of having a 15% solution. To get down to 15%, we must add more than 4 gallons of the weaker (less saline) solution. However, since adding 4 gallons of the 7% solution bought us VERY CLOSE to our goal of having a 15% solution, we only need to add a LITTLE MORE THAN 4 gallons of 7% solution to reach the goal salinity of 15%.
Since only one answer choice (C) is a little more than 4, we can conclude that 5 is the correct answer.