GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
WE:Education (Education)
In the figure above, BD and CE are two diameters of circle
[#permalink]
07 Sep 2021, 09:13
07 Sep 2021, 09:13
1
7
Bookmarks
00:00
Question Stats:
41% (02:25) correct
58% (01:51) wrong based on 34 sessions
Hide Show timer Statistics
Attachment:
In the figure above, BD and CE are two diameters.png [ 6.31 KiB | Viewed 2338 times ]
In the figure above, BD and CE are two diameters of circle intersecting each other at 48°.
Points A, B, C, D, and E - all lie on the circle.
Quantity A |
Quantity B |
m∠EAB |
130° |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
WE:Education (Education)
Re: In the figure above, BD and CE are two diameters of circle
[#permalink]
19 Sep 2021, 01:49
19 Sep 2021, 01:49
2
freak47 wrote:
Can someone please explain this more clearly?
Usind the property of Central angle:
\(∠EAB = \frac{1}{2}(∠EOB)\)
\(∠EAB = \frac{1}{2}(48° + 48° + 132°) = \frac{228°}{2} = 114°\)
Col. A: 114°
Col. B: 130°
Hence, option B
Attachments
In the figure above, BD and CE are two diameters.png [ 7.91 KiB | Viewed 2070 times ]
General Discussion
Re: In the figure above, BD and CE are two diameters of circle
[#permalink]
09 Sep 2021, 04:12
09 Sep 2021, 04:12
1
Assume that O is the center of the circle. The mes of angle EOB that intercepts the small arc EB is (360- (48×2)/2= 132
The mes of the external angle EOB that intercept the large arc EB is 360-132= 228
Angle EAB intercept the same large arc that the angle center EOB. So mes of EAB = 228/2=114
Quant A < quant B
Answer B
Posted from my mobile device
The mes of the external angle EOB that intercept the large arc EB is 360-132= 228
Angle EAB intercept the same large arc that the angle center EOB. So mes of EAB = 228/2=114
Quant A < quant B
Answer B
Posted from my mobile device
