Carcass wrote:
A driver completed the first 20 miles of a 40-mile trip at an average speed of 50 miles per hour and the second 20 miles at an average speed of x miles per hour. The average speed for the entire 40-mile trip was 60 miles per hour. (Assume that the driver did not make any stops during the 40-mile trip.)
Quantity A |
Quantity B |
x-60 |
10 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Source:
manhattanreviewAverage speed\( = \frac{total distance travelled}{ total travel time}\)
The driver travels a total distance of 40 miles, and were told that the average speed was 60 miles per hour.
Plug in those values to get: \( 60= \frac{40}{ total travel time}\)
Now let's calculate
total travel timetotal travel time = (time spent driving the first 20 miles) + (time spent driving the last 20 miles)
Since \(time = \frac{distance}{speed}\), we get:
total travel time \(= \frac{20}{50} + \frac{20}{x}\)
total travel time \(= \frac{20x}{50x} + \frac{1000}{50x}\)
total travel time \(= \frac{20x+1000}{50x} \)
Plug this into our equation: \( 60= \frac{40}{(\frac{20x+1000}{50x})}\)
Rewrite as follows: \( 60= (40)(\frac{50x}{20x+1000})\)
Simplify: \( 60= \frac{2000x}{20x+1000}\)
Multiply both sides of the equation by \(20x+1000\) to get: \(1200x +60,000 = 2000x\)
Subtract \(1200x\) from both sides to get: \(60,000 = 800x\)
Divide both sides by \(800\) to get: \(75 = x\)
So we have:
QUANTITY A: \(x - 60 = 75 - 60 = 15\)
QUANTITY B: \(10\)
Answer: A