GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Retired Moderator
Joined: 16 Apr 2020
Status:Founder & Quant Trainer
Affiliations: Prepster Education
Posts: 1546
Given Kudos: 172
Location: India
WE:Education (Education)
In a class of n students, certain number of badges were distributed.
[#permalink]
23 Sep 2021, 05:16
23 Sep 2021, 05:16
3
Bookmarks
00:00
Question Stats:
36% (02:07) correct
63% (01:21) wrong based on 11 sessions
Hide Show timer Statistics
In a class of \(n\) students, certain number of badges were distributed. The student who got \(\frac{1}{6}^{th}\) of the total number of badges actually got 5 times the average number of badges the others got.
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Quantity A |
Quantity B |
\(n\) |
26 |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Retired Moderator
Joined: 19 Nov 2020
Posts: 326
Given Kudos: 64
GRE 1: Q160 V152
Re: In a class of n students, certain number of badges were distributed.
[#permalink]
24 Sep 2021, 15:20
24 Sep 2021, 15:20
1
if \(x\) is the number of all badges, then \(x/6=5(x-x/6):(n-1)\)
\(x/6=25x/6:(n-1)\), \(\frac{x(n-1)-25x}{6(n-1)}=0\)
\(x(n-1)-25x=0\), \(x(n-1-25)=0\) has two roots \(x=0\), which is not possible and \(n=26\) that is accepted
answer is C
\(x/6=25x/6:(n-1)\), \(\frac{x(n-1)-25x}{6(n-1)}=0\)
\(x(n-1)-25x=0\), \(x(n-1-25)=0\) has two roots \(x=0\), which is not possible and \(n=26\) that is accepted
answer is C
KarunMendiratta wrote:
In a class of \(n\) students, certain number of badges were distributed. The student who got \(\frac{1}{6}^{th}\) of the total number of badges actually got 5 times the average number of badges the others got.
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Quantity A |
Quantity B |
\(n\) |
26 |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Re: In a class of n students, certain number of badges were distributed.
[#permalink]
24 Sep 2021, 21:53
24 Sep 2021, 21:53
motion2020 wrote:
if \(x\) is the number of all badges, then \(x/6=5(x-x/6):(n-1)\)
\(x/6=25x/6:(n-1)\), \(\frac{x(n-1)-25x}{6(n-1)}=0\)
\(x(n-1)-25x=0\), \(x(n-1-25)=0\) has two roots \(x=0\), which is not possible and \(n=26\) that is accepted
answer is C
\(x/6=25x/6:(n-1)\), \(\frac{x(n-1)-25x}{6(n-1)}=0\)
\(x(n-1)-25x=0\), \(x(n-1-25)=0\) has two roots \(x=0\), which is not possible and \(n=26\) that is accepted
answer is C
KarunMendiratta wrote:
In a class of \(n\) students, certain number of badges were distributed. The student who got \(\frac{1}{6}^{th}\) of the total number of badges actually got 5 times the average number of badges the others got.
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Quantity A |
Quantity B |
\(n\) |
26 |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
(n-1) plz eplain.
