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A certain fish tank holds a total of 42 fish among four compartments.
[#permalink]
27 Sep 2021, 05:09
27 Sep 2021, 05:09
Expert Reply
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Question Stats:
75% (01:27) correct
25% (01:37) wrong based on 16 sessions
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A certain fish tank holds a total of 42 fish among four compartments. If the numbers of fish in the compartments are consecutive, what is the probability that a given fish is in the compartment that holds the most fish?
(A) 11/42
(B) 5/21
(C) 1/4
(D) 3/14
(E) 2/7
(A) 11/42
(B) 5/21
(C) 1/4
(D) 3/14
(E) 2/7
Re: A certain fish tank holds a total of 42 fish among four compartments.
[#permalink]
28 Sep 2021, 08:55
28 Sep 2021, 08:55
1
Carcass wrote:
A certain fish tank holds a total of 42 fish among four compartments. If the numbers of fish in the compartments are consecutive, what is the probability that a given fish is in the compartment that holds the most fish?
(A) 11/42
(B) 5/21
(C) 1/4
(D) 3/14
(E) 2/7
(A) 11/42
(B) 5/21
(C) 1/4
(D) 3/14
(E) 2/7
Let four consecutive numbers be x-1,x,x+1 and x+2. And since the sum is 42, x will be 10.
so the compartments contains fish of quantity, 9,10,11 and 12. And largest is 12, so the P(from tank of 12) = 12/42 = 2/7;
Answer is E)
gmatclubot
Re: A certain fish tank holds a total of 42 fish among four compartments. [#permalink]
28 Sep 2021, 08:55
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