Carcass wrote:
A bowl contains 15 marbles, all of which are either red or blue. If the number of red marbles is one more than the number of blue marbles, what is the probability that a marble selected at random is blue?
A. 1/15
B. 2/15
C. 7/15
D. 1/2
E. 8/15
The number of red marbles is one more than the number of blue marbles. And there are 15 marbles in totalLet B = # of blue marbles
So, B + 1= # of red marbles
Since there are 15 marbles in total, we get: B + (B + 1) =15
Simplify: 2B + 1 = 15
So 2B = 14
B = 7
So, there are 7 blue marbles and 8 red marbles
What is the probability that a marble selected at random is blue?P(blue) = 7/15
Answer: C