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There are 5 couples. If they will sit 10 chairs in a row such that eac
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06 Oct 2021, 09:26
2
Carcass wrote:
There are 5 couples. If they will sit 10 chairs in a row such that each couple sits side by side, how many possible cases are there?
A. 120 B. 240 C. 1,200 D. 2,460 E. 3,840
Here's one approach:
Take the task of seating the 10 people and break it into stages.
Stage 1: Select someone to sit in the 1st chair There are 10 people to choose from, so we can complete stage 1 in 10 ways
Stage 2: Select someone to sit in the 2nd chair The person seated in the 2nd chair must be the partner of the person in the 1st chair So we can complete this stage in 1 way.
Stage 3: Select someone to sit in the 3rd chair There are 8 people remaining. So, we can complete stage 3 in 8 ways
Stage 4: Select someone to sit in the 4th chair The person seated in the 4th chair must be the partner of the person in the 3rd chair So, we can complete this stage in 1 way.
Stage 5: Select someone to sit in the 5th chair There are 6 people remaining. So, we can complete stage 5 in 6 ways
Stage 6: Select someone to sit in the 6th chair The person seated in the 6th chair must be the partner of the person in the 5th chair So, we can complete this stage in 1 way.
Stage 7: Select someone to sit in the 7th chair There are 4 people remaining. So, we can complete stage 7 in 4 ways
Stage 8: Select someone to sit in the 8th chair The person seated in the 8th chair must be the partner of the person in the 7th chair So, we can complete this stage in 1 way.
Stage 9: Select someone to sit in the 9th chair There are 2 people remaining. So, we can complete stage 9 in 2 ways
Stage 10: Select someone to sit in the 10th chair One 1 person remains. So, we can complete this stage in 1 way.
By the Fundamental Counting Principle (FCP), we can complete all 10 stages (and thus seat all 10 people) in (10)(1)(8)(1)(6)(1)(4)(1)(2)(1) ways (= 3840 ways)
Answer: E
Note: the FCP can be used to solve the MAJORITY of counting questions on the GRE, so be sure to learn it.
Re: There are 5 couples. If they will sit 10 chairs in a row such that eac
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06 Oct 2021, 14:07
2
10 people means 5 couple. 5 couple can be arranged in 5*4*3*2*1=120 ways another couple means two people and they can sit as H,W or W,H =2*1 for 5 couple =2*2*2*2*2=32 total number of ways it can be arranged=120*32=3840.