Explanation:

Let us assume a circle with centre at origin and radius 5 units.
Equation of circle: \((x - 0)^2 + (y - 0)^2 = 25\)

Now, x and y are integers
Let us see what all points we can have;
when x = 0, y = 5
when x = 3, y = 4
when x = 4, y = 3
when x = 5, y = 0

Let us first try solving using (3, 4)

consider a new circle with centre (3, 4) and radius 5 units
equation of new circle: \((x - 3)^2 + (y - 4)^2 = 25\)

What are points on x-axis and y-axis from which the circle passes?

for x-intercept, plug y = 0
so, \((x - 3)^2 + (0 - 4)^2 = 25\)
i.e. x = 6

for y-intercept, plug x = 0
so, \((0 - 3)^2 + (y - 4)^2 = 25\)
i.e. y = 8

Now, is (0, 8) 5 units from the end point (1, 0)? - NO
Is (6, 0) 5 units from the end point (1, 0)? - YES

Voila, we can do it in 3 jumps

Col. A: 3
Col. B: 4

Hence, option B