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1<s<t<u
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Updated on: 10 Oct 2021, 02:00
Updated on: 10 Oct 2021, 02:00
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Question Stats:
33% (01:02) correct
66% (01:36) wrong based on 6 sessions
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\(1<s<t<u\)
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Quantity A |
Quantity B |
(\(\frac{1}{s})+(\frac{1}{t})+(\frac{1}{u}\)) |
1 |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Re: 1<s<t<u
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09 Oct 2021, 09:07
09 Oct 2021, 09:07
Expert Reply
Please see here how to use the timer https://gre.myprepclub.com/forum/how-to-po ... 12752.html
We can have integers as s,t, and u and the fraction in A <B
But if above one we do have fractions then we do have an integer in A that is > B
D is the answer
We can have integers as s,t, and u and the fraction in A <B
But if above one we do have fractions then we do have an integer in A that is > B
D is the answer
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1<s<t<u
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10 Oct 2021, 05:51
10 Oct 2021, 05:51
1
mnaveed wrote:
\(1<s<t<u\)
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Quantity A |
Quantity B |
(\(\frac{1}{s})+(\frac{1}{t})+(\frac{1}{u}\)) |
1 |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Since s, t and u are each greater than 1, we know that 1/s, 1/t, and 1/u will each be less than one.
At this point we might check some EXTREME values.
We'll test values of s, t and u that are just a little bit greater than 1, and we'll test values that are much greater than 1.
For example, if s = 1.01, t = 1.02, and u = 1.03, we know that 1/s, 1/t and 1/u are each just a little bit less than 1.
This means 1/s + 1/t + 1/u will be a little bit less than 3, which means Quantity A is greater
Now let's test test values that are much greater than 1.
For example, if s = 100,001, t = 100,002, and u = 100,003, we know that 1/s, 1/t and 1/u are each close to zero.
This means, 1/s + 1/t + 1/u will be close to zero, which means Quantity B is greater
Answer: D
