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There are 4 Fashion magazines and 4 Car magazines. Four magazines are
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15 Oct 2021, 04:51
15 Oct 2021, 04:51
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Question Stats:
90% (00:52) correct
9% (00:27) wrong based on 11 sessions
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There are 4 Fashion magazines and 4 Car magazines. Four magazines are drawn at random, what is the probability that all fashion magazines will be drawn?
A. 1
B. 1/21/2
C. 1/31/3
D. 1/81/8
E. 1/70
A. 1
B. 1/21/2
C. 1/31/3
D. 1/81/8
E. 1/70
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Re: There are 4 Fashion magazines and 4 Car magazines. Four magazines are
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15 Oct 2021, 05:21
15 Oct 2021, 05:21
1
Carcass wrote:
There are 4 Fashion magazines and 4 Car magazines. Four magazines are drawn at random, what is the probability that all fashion magazines will be drawn?
A. 1
B. 1/21/2
C. 1/31/3
D. 1/81/8
E. 1/70
A. 1
B. 1/21/2
C. 1/31/3
D. 1/81/8
E. 1/70
P(all 4 draws are fashion magazines) = P(1st draw is fashion AND 2nd draw is fashion AND 3rd draw is fashion AND 4th draw is fashion)
= P(1st draw is fashion) x P(2nd draw is fashion) x P(3rd draw is fashion) x P(4th draw is fashion)
= 4/8 x 3/7 x 2/6 x 1/5
= 1/70
Answer: E
ASIDE: When we start, 4 of the 8 magazines are fashion magazines. This is why the first probability is 4/8.
When we choose a fashion magazine for the 1st draw, there are 7 magazines remaining, and 3 of them are fashion magazines. This is why the second probability is 3/7
And so on....
Cheers,
Brent
gmatclubot
Re: There are 4 Fashion magazines and 4 Car magazines. Four magazines are [#permalink]
15 Oct 2021, 05:21
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