Carcass wrote:
Jayden has two coins in his pocket, each of which are either a penny, a nickel, a dime, or a quarter, and they are not the same. If the first coin is worth ten cents less than four times the value of the second coin, what is the total value of the two coins?
(A) $0.06
(B) $0.11
(C) $0.15
(D) $0.30
(E) $0.35
The allowed coin values are 1,5,10 and 25.
Let first coin be x and second coin be y, so relation is x = 4y -10 and the only values that satisfies are y = 5 and x = 10.
so x+y = 15 cents or $.15
Answer is C)