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At what value of x does the function
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02 Nov 2021, 07:44
02 Nov 2021, 07:44
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At what value of x does the function , \(y=\frac{(x-2)^2(x+3)}{(x-2)^3(x+3)}\) have a vertical asymptote?
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Re: At what value of x does the function
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02 Nov 2021, 19:52
02 Nov 2021, 19:52
1
Vertical asymptotes can be found by solving the equation f(x) = 0 where f(x) is the denominator of the function
From the given equation, it is clear that when \(x = 2\), the function will have vertical asymptotes.
Answer \(x = 2\)
From the given equation, it is clear that when \(x = 2\), the function will have vertical asymptotes.
Answer \(x = 2\)
Re: At what value of x does the function
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20 Jul 2023, 10:08
20 Jul 2023, 10:08
can someone explain this elaborately please?
