Carcass wrote:
If x and y are integers, and 5x +3y = 15, which of the following could NOT be the value of y?
(A) −5
(B) 0
(C) 3
(D) 5
(E) 1005
Given: 5x +3y = 15
Divide both sides by 15 to get:
x/3 + y/5 = 1At this point we can see that, if y is a multiple of 5, then y/5 will be an integer, which means we'll be able to find an integer value of x that satisfies the equation.
For example, if y = -5, we get x/3 + (-5)/5 = 1, which means x = 6
Similarly, if y = 1005, we get x/3 + 1005/5 = 1, which means x = -600
Since 3 is NOT a multiple of 5, the correct answer is C