GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 17Live Online Classes with Top GRE Expert Rich Zwelling
08:00 PM EST
-10:00 PM EST
Get live instruction from a top-scoring, industry-recognized GRE teachers + 6 months of access to TTP Self-Study included! Tues/Thur Sept 7, 2026---Feb. 2, 2027, 1:00pm-3:00pm EST
Dec 14Live Online Classes with Top GRE Expert Michael Butville
08:00 PM EST
-10:00 PM EST
Get live instruction from a top-scoring, industry-recognized GRE teachers + 6 months of access to TTP Self-Study included! Mon/Wed Dec. 14, 2026---Feb. 22, 2027, 8:00pm-10:00pm EST
GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2949
Given Kudos: 1287
GPA: 3.39
If x < y < z and y - x > 5, where x is an even integer and y and z are
[#permalink]
05 Nov 2021, 07:30
05 Nov 2021, 07:30
Expert Reply
00:00
Question Stats:
50% (01:12) correct
50% (01:29) wrong based on 8 sessions
Hide Show timer Statistics
If x < y < z and y - x > 5, where x is an even integer and y and z are odd integers, what is the least possible value of z - x?
A. 6
B. 7
C. 8
D. 9
E. 10
A. 6
B. 7
C. 8
D. 9
E. 10
If x < y < z and y - x > 5, where x is an even integer and y and z are
[#permalink]
08 Nov 2021, 19:47
08 Nov 2021, 19:47
1
\(x < y < z\) & \(y - x > 5\)
\(x\) even & \(y , z\) are odd
We need to find the least difference, so we will take the least value.
Let's take \(x = 2\) so \(y > 7\)
\(y = 9\) & \(z = 11\)
The least value for \(z - x = 9\)
Answer D
\(x\) even & \(y , z\) are odd
We need to find the least difference, so we will take the least value.
Let's take \(x = 2\) so \(y > 7\)
\(y = 9\) & \(z = 11\)
The least value for \(z - x = 9\)
Answer D
Re: If x < y < z and y - x > 5, where x is an even integer and y and z are
[#permalink]
21 Jul 2022, 00:28
21 Jul 2022, 00:28
Solution -
y is odd and x is even, so (y - x) has to be odd. ( y - x ) > 5 means ( y - x ) can have a value of 7.
y - x = 7;
=> y = x + 7
The main equation will become,
x < (x + 7) < z
Subtract x from all,
0 < 7 < (z - x)
Since z is odd and x is even, (z - x) has to be odd.
As (z - x) > 7, the least possible value of (z - x) will be 9.
Answer D
y is odd and x is even, so (y - x) has to be odd. ( y - x ) > 5 means ( y - x ) can have a value of 7.
y - x = 7;
=> y = x + 7
The main equation will become,
x < (x + 7) < z
Subtract x from all,
0 < 7 < (z - x)
Since z is odd and x is even, (z - x) has to be odd.
As (z - x) > 7, the least possible value of (z - x) will be 9.
Answer D
