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GRE Math Challenge #57- Quantity A: (2+3x)/2

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sandy
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GRE Math Challenge #57- Quantity A: (2+3x)/2 [#permalink] New post   Updated on: 19 Feb 2020, 09:57
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Question Stats:

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Quantity A
Quantity B
\(\frac{(2+3x)}{2}\)
\(1+3x\)



A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

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D

Originally posted by sandy on 03 May 2015, 00:45.
Last edited by Carcass on 19 Feb 2020, 09:57, edited 1 time in total.
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GreenlightTestPrep
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Re: GRE Math Challenge #57 [#permalink] New post   18 May 2015, 11:51
2
sandy wrote:
Quantity A: \((2+3x)/2\)

Quantity B: \(1+3x\)


Let's use the technique of performing the same operation on each quantity. By the way, we have a free video on this strategy here: http://www.greenlighttestprep.com/module/gre-quantitative-comparison?id=1097

Okay, first multiply both quantities by 2 to get:
Quantity A: 2 + 3x
Quantity B: 2 + 6x

Subtract 2 from both quantities to get:
Quantity A: 3x
Quantity B: 6x

Subtract 3x from both quantities to get:
Quantity A: 0
Quantity B: 3x

Since x can be positive or negative (or even zero), there's no way to determine which quantity is greater.
Answer:
Show: ::
D


Cheers,
Brent
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Re: GRE Math Challenge #57- Quantity A: (2+3x)/2 [#permalink] New post   19 Feb 2022, 02:12
Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: GRE Math Challenge #57- Quantity A: (2+3x)/2 [#permalink]
19 Feb 2022, 02:12
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