Carcass wrote:
If \(0 < a < \frac{1}{b} <1\) then which of the following must be true ?
(A) \(a > b > b^2\)
(B) \(b > a > a^2 > b^2\)
(C) \(b^2 > a > a^2 > b\)
(D) \(b^2 > a^2 > b > a\)
(E) \(b^2 > b > a > a^2\)
I believe the fastest approach is to find values for \(a\) and \(b\) that satisfy the condition \(0 < a < \frac{1}{b} <1\)
So, for example, it could be the case that \(a = 0.1\) and \(b = 2\), in which case \(a^2 = 0.01\) and \(b^2 = 4\)
When we arrange all 4 values, we get \(b^2 > b > a > a^2\)
Answer: E