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7^9+7^9+7^9+7^9+7^9+7^9+7^9=7^x
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Updated on: 03 Dec 2021, 11:28
Updated on: 03 Dec 2021, 11:28
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\(7^9+7^9+7^9+7^9+7^9+7^9+7^9=7^x\), then x=
A. 9
B. 10
C. 12
D. 63
E. \(9^7\)
Posted from my mobile device
A. 9
B. 10
C. 12
D. 63
E. \(9^7\)
Posted from my mobile device
Originally posted by schrodinger on 03 Dec 2021, 11:17.
Last edited by Carcass on 03 Dec 2021, 11:28, edited 1 time in total.
Last edited by Carcass on 03 Dec 2021, 11:28, edited 1 time in total.
Updated
Re: 7^9+7^9+7^9+7^9+7^9+7^9+7^9=7^x
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03 Dec 2021, 11:23
03 Dec 2021, 11:23
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Expert Reply
In such type of questions, we tend to have the same base on both sides so we could compare the exponents.
First, we simplify the expression by adding all the terms on the left hand side.
\((7)7^9=7^x\)
\(7^{9+1}=7^x\)
\(7^{10}=7^x\)
Hence, x=10. So the answer is B.
First, we simplify the expression by adding all the terms on the left hand side.
\((7)7^9=7^x\)
\(7^{9+1}=7^x\)
\(7^{10}=7^x\)
Hence, x=10. So the answer is B.
gmatclubot
Re: 7^9+7^9+7^9+7^9+7^9+7^9+7^9=7^x [#permalink]
03 Dec 2021, 11:23
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