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If a and b are integers and 4 < a < b ≤ 8, what is the maximum possib
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05 Dec 2021, 16:48
05 Dec 2021, 16:48
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Question Stats:
66% (01:40) correct
33% (01:29) wrong based on 21 sessions
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This question is part of the GRE - Skill Builder Project for a Q170
If a and b are integers and \(4 < a < b ≤ 8\), what is the maximum possible value of \(\frac{b-a}{ab}\)?
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Re: If a and b are integers and 4 < a < b ≤ 8, what is the maximum possib
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05 Dec 2021, 19:23
05 Dec 2021, 19:23
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\(4 < a < b ≤ 8\) with \(a\) & \(b\) are integers.
\(\frac{b-a}{ab}\)
Simplifying the equation,
\(\frac{1}{a} - \frac{1}{b}\)
To get the max value, we will need the lowest value of \(a\) and the highest value of \(b\)
So \(a = 5\) & \(b = 8\)
\(\frac{1}{5} - \frac{1}{8}\)
\(\frac{3}{40}\)
Answer 3/40
\(\frac{b-a}{ab}\)
Simplifying the equation,
\(\frac{1}{a} - \frac{1}{b}\)
To get the max value, we will need the lowest value of \(a\) and the highest value of \(b\)
So \(a = 5\) & \(b = 8\)
\(\frac{1}{5} - \frac{1}{8}\)
\(\frac{3}{40}\)
Answer 3/40
Re: If a and b are integers and 4 < a < b 8, what is the maximum possib
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15 Oct 2025, 19:29
15 Oct 2025, 19:29
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