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(x^3/y^4)^-2
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09 Dec 2021, 02:26
09 Dec 2021, 02:26
Expert Reply
00:00
Question Stats:
84% (01:25) correct
15% (01:17) wrong based on 13 sessions
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\(\frac{(\frac{x^3}{y^4})^{-2}}{(\frac{x^2}{y^3})^4}\)
A. \(\frac{y^{20}}{x^{14}
}\)
B. \(\frac{y^4}{x^2}\)
C. \(\frac{x^2}{y^4}\)
D. \(\frac{y^5}{x^4}\)
E. \(\frac{y^8}{x^5}\)
A. \(\frac{y^{20}}{x^{14}
}\)
B. \(\frac{y^4}{x^2}\)
C. \(\frac{x^2}{y^4}\)
D. \(\frac{y^5}{x^4}\)
E. \(\frac{y^8}{x^5}\)
(x^3/y^4)^-2
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09 Dec 2021, 02:50
09 Dec 2021, 02:50
1
Expert Reply
We begin with the simplification of the given expression to arrive at the correct answer.
Solving the exponents, we get
\(\frac{\frac{x^{-6}}{y^{-8}}}{\frac{x^8}{y^{12}}}\)
After simplification, we get
\(\frac{y^{20}}{x^{14}}\). Hence, the answer is A.
Solving the exponents, we get
\(\frac{\frac{x^{-6}}{y^{-8}}}{\frac{x^8}{y^{12}}}\)
After simplification, we get
\(\frac{y^{20}}{x^{14}}\). Hence, the answer is A.
Re: (x^3/y^4)^-2
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09 Dec 2021, 09:22
09 Dec 2021, 09:22
1
(x^-6 / y^-8) ÷ (x^8 / y^12)
(y^8 / x^6) × (y^12 / x^8)
y^(8+12) / x^(6+8)
y^20 / x^14
Ans - A
Posted from my mobile device
(y^8 / x^6) × (y^12 / x^8)
y^(8+12) / x^(6+8)
y^20 / x^14
Ans - A
Posted from my mobile device
