GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
In the figure, ABC and ADC are right triangles. Which of the
[#permalink]
17 Mar 2019, 03:02
17 Mar 2019, 03:02
Expert Reply
1
Bookmarks
00:00
Question Stats:
64% (02:10) correct
35% (03:02) wrong based on 31 sessions
Hide Show timer Statistics
Attachment:
#GREpracticequestion In the figure, ABC and ADC are right triangle..jpg [ 16.2 KiB | Viewed 7042 times ]
In the figure, ABC and ADC are right triangles. Which of the following could be the lengths of AD and DC, respectively?
(I) \(\sqrt{3}\) and \(\sqrt{4}\)
(II) 4 and 6
(III) 1 and \(\sqrt{24}\)
(IV) 1 and \(\sqrt{26}\)
(A) I and II only
(B) II and III only
(C) III and IV only
(D) IV and I only
(E) I, II and III only
Re: In the figure, ABC and ADC are right triangles. Which of the
[#permalink]
20 Mar 2019, 10:54
20 Mar 2019, 10:54
3
Expert Reply
We can use the Pythagorean theorem to find the length of AC:
\(3^{2} + 4^{2} = (AC)^{2}\)
\(9 + 16 = (AC)^{2}\)
\(25 = (AC)^{2}\)
\(5 = AC\)
We should also recognize this as a 3-4-5 triangle, one of the Pythagorean triplets.
In any case, we know that ADC is a right triangle, but we don't know which angle is the right angle. So, any of these three possibilities could be correct, depending on which side is the hypotenuse:
\(AD^{2} + DC^{2} = AC^{2}\)
\(AD^{2} + AC^{2} = DC^{2}\)
\(AC^{2} + DC^{2} = AD^{2}\)
Plug in AC = 5, and we get these possible equations:
\(AD^{2} + DC^{2} = 25\)
\(AD^{2} + 25 = DC^{2}\)
\(25 + DC^{2} = AD^{2}\)
I want to isolate the known value, 25:
\(25 = AD^{2} + DC^{2}\)
\(25 = DC^{2} - AD^{2}\)
\(25 = AD^{2} - DC^{2}\)
Now we can just plug in the answer choices. Clearly the first statement won't work, as 3 and 4 are much too small to add up to 25. Already that eliminates choices A, D, and E.
The second statement is pretty easy to eliminate as well, since 4² and 6² = 16 and 36, respectively. But no combination of adding or subtract 16 and 36 will give us an answer of 25. So Statement II must be false, and the answer must be C.
\(3^{2} + 4^{2} = (AC)^{2}\)
\(9 + 16 = (AC)^{2}\)
\(25 = (AC)^{2}\)
\(5 = AC\)
We should also recognize this as a 3-4-5 triangle, one of the Pythagorean triplets.
In any case, we know that ADC is a right triangle, but we don't know which angle is the right angle. So, any of these three possibilities could be correct, depending on which side is the hypotenuse:
\(AD^{2} + DC^{2} = AC^{2}\)
\(AD^{2} + AC^{2} = DC^{2}\)
\(AC^{2} + DC^{2} = AD^{2}\)
Plug in AC = 5, and we get these possible equations:
\(AD^{2} + DC^{2} = 25\)
\(AD^{2} + 25 = DC^{2}\)
\(25 + DC^{2} = AD^{2}\)
I want to isolate the known value, 25:
\(25 = AD^{2} + DC^{2}\)
\(25 = DC^{2} - AD^{2}\)
\(25 = AD^{2} - DC^{2}\)
Now we can just plug in the answer choices. Clearly the first statement won't work, as 3 and 4 are much too small to add up to 25. Already that eliminates choices A, D, and E.
The second statement is pretty easy to eliminate as well, since 4² and 6² = 16 and 36, respectively. But no combination of adding or subtract 16 and 36 will give us an answer of 25. So Statement II must be false, and the answer must be C.
Re: In the figure, ABC and ADC are right triangles. Which of the
[#permalink]
10 May 2019, 08:01
10 May 2019, 08:01
Can someone please explain C (especially IV option) is correct ? Thank you
