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Which one of the following equations has a root in common with [m]m^2
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13 Dec 2021, 04:50
13 Dec 2021, 04:50
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Which one of the following equations has a root in common with \(m^2 + 4m + 4 = 0\) ?
A. \(m^2 − 4m + 4 = 0\)
B. \(m^2 + 4m + 3 = 0\)
C. \(m^2 − 4 = 0\)
D. \(m^2 + m − 6 =0\)
E. \(m^2 + 5m + 4 = 0\)
A. \(m^2 − 4m + 4 = 0\)
B. \(m^2 + 4m + 3 = 0\)
C. \(m^2 − 4 = 0\)
D. \(m^2 + m − 6 =0\)
E. \(m^2 + 5m + 4 = 0\)
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Re: Which one of the following equations has a root in common with [m]m^2
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13 Dec 2021, 06:29
13 Dec 2021, 06:29
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Carcass wrote:
Which one of the following equations has a root in common with \(m^2 + 4m + 4 = 0\) ?
A. \(m^2 − 4m + 4 = 0\)
B. \(m^2 + 4m + 3 = 0\)
C. \(m^2 − 4 = 0\)
D. \(m^2 + m − 6 =0\)
E. \(m^2 + 5m + 4 = 0\)
A. \(m^2 − 4m + 4 = 0\)
B. \(m^2 + 4m + 3 = 0\)
C. \(m^2 − 4 = 0\)
D. \(m^2 + m − 6 =0\)
E. \(m^2 + 5m + 4 = 0\)
Given: \(m^2 + 4m + 4 = 0\)
Factor: \((m + 2)(m + 2) = 0\)
So, it must be the case that \(m = -2\)
Now plug \(m = -2\) into each of the answer choices to see which one is a solution (root) to that equation...
A. \(m^2 − 4m + 4 = 0\)
\(\rightarrow(-2)^2 − 4(-2) + 4 = 0\)
\(\rightarrow 4 +8 + 4 = 0\)
\(\rightarrow16 = 0\)
\(m = -2\) is NOT a solution to this equation.
B. \(m^2 + 4m + 3 = 0\)
\(\rightarrow(-2)^2 + 4(-2) + 3 = 0\)
\(\rightarrow4 -8 + 3 = 0\)
\(\rightarrow1 = 0\)
\(m = -2\) is NOT a solution to this equation.
C. \(m^2 − 4 = 0\)
\(\rightarrow(-2)^2 − 4 = 0\)
\(\rightarrow4 − 4 = 0\)
\(\rightarrow0 = 0\)
\(m = -2\) IS a solution to this equation.
Answer: C
gmatclubot
Re: Which one of the following equations has a root in common with [m]m^2 [#permalink]
13 Dec 2021, 06:29
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