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The mean of twenty-five consecutive positive integers number
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15 Oct 2017, 22:56
15 Oct 2017, 22:56
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Question Stats:
72% (01:24) correct
27% (01:04) wrong based on 18 sessions
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The mean of twenty-five consecutive positive integers numbers is what percent of the total?
(A) 4%
(B) 5%
(C) 20%
(D) 25%
(E) Cannot be determined by the information provided.
Kudos for correct solution.
(A) 4%
(B) 5%
(C) 20%
(D) 25%
(E) Cannot be determined by the information provided.
Kudos for correct solution.
Re: The mean of twenty-five consecutive positive integers number
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15 Oct 2017, 23:39
15 Oct 2017, 23:39
2
Let's take integers from 1 to 25, which are twenty-five positive consecutive integers. Then, their mean would be computed as \(\frac{1+2+3+\dots+25}{25} = x\).
Thus, the mean x of those numbers is \(\frac{x}{1+2+\dots+25}=\frac{1}{25}*100=4%\) of their sum.
Answer A
Thus, the mean x of those numbers is \(\frac{x}{1+2+\dots+25}=\frac{1}{25}*100=4%\) of their sum.
Answer A
Re: The mean of twenty-five consecutive positive integers number
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15 Dec 2021, 03:19
15 Dec 2021, 03:19
Expert Reply
