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The side of equilateral triangle T is the same as the length
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06 Sep 2019, 05:55
06 Sep 2019, 05:55
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Question Stats:
88% (00:42) correct
11% (00:28) wrong based on 59 sessions
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The side of equilateral triangle T is the same as the length of a side of square S.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
The area of triangle T |
The area of square S |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Re: The side of equilateral triangle T is the same as the length
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06 Sep 2019, 07:49
06 Sep 2019, 07:49
1
Area of equilateral triangle is given by:
\(\frac{\sqrt{3}}{4}\) s^2 where s is a side of the triangle.
Area of square = \(l^2\) where l = length of a side of the square
From question l = s
hence,
Qty A simplifies to \(\frac{\sqrt{3}}{4} s^2\)
Qty B simplifies to \(s^2\)
Cancel \(s^2\) from both side
Qty A = \(\frac{\sqrt{3}}{4}\)
Qty B = 1
B is greater
\(\frac{\sqrt{3}}{4}\) s^2 where s is a side of the triangle.
Area of square = \(l^2\) where l = length of a side of the square
From question l = s
hence,
Qty A simplifies to \(\frac{\sqrt{3}}{4} s^2\)
Qty B simplifies to \(s^2\)
Cancel \(s^2\) from both side
Qty A = \(\frac{\sqrt{3}}{4}\)
Qty B = 1
B is greater
Re: The side of equilateral triangle T is the same as the length
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06 Sep 2019, 20:30
06 Sep 2019, 20:30
1
Area of equilateral triangle is given by:
[squareroot]3[squareroot]/4[squareroot]3[squareroot]/4 s^2 where s is a side of the triangle.
Area of square = l2l2 where l = length of a side of the square
From question l = s
hence,
Qty A simplifies to [squareroot]3[squareroot]/4s2[squareroot]3[squareroot]/4s2
Qty B simplifies to s2s2
Cancel s2s2 from both side
Qty A = [squareroot]3[squareroot]/4[squareroot]3[squareroot]/4
Qty B = 1
B is greater
[squareroot]3[squareroot]/4[squareroot]3[squareroot]/4 s^2 where s is a side of the triangle.
Area of square = l2l2 where l = length of a side of the square
From question l = s
hence,
Qty A simplifies to [squareroot]3[squareroot]/4s2[squareroot]3[squareroot]/4s2
Qty B simplifies to s2s2
Cancel s2s2 from both side
Qty A = [squareroot]3[squareroot]/4[squareroot]3[squareroot]/4
Qty B = 1
B is greater
