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ABC is a right triangle with legs of length x/y
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28 Dec 2021, 06:24
28 Dec 2021, 06:24
1
Expert Reply
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Question Stats:
86% (01:20) correct
13% (01:26) wrong based on 23 sessions
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ABC is a right triangle with legs of length \(\frac{x}{y}\) and \(y\)
The quantity in Column A is greater
The quantity in Column B is greater
The two quantities are equal
The relationship cannot be determined from the information given
Quantity A |
Quantity B |
\(\frac{x[5-\sqrt{17}][\sqrt{17}+5]}{\sqrt{256}}\) |
The area of triangle ABC |
The quantity in Column A is greater
The quantity in Column B is greater
The two quantities are equal
The relationship cannot be determined from the information given
ABC is a right triangle with legs of length x/y
[#permalink]
28 Dec 2021, 11:33
28 Dec 2021, 11:33
1
Quantity A:
\(\frac{x(5−√17)(√17+5)}{√256} = \frac{(5x−x√17)(√17+5)}{√256} = \frac{(5x√17 + 25 x - 17 x - 5x√17)}{√256} = \frac{8x}{√256} = \frac{8x}{16} = \frac{x}{2}\)
Quantity B:
Area of ABC = ( y * [x/y] )/2 = \(\frac{x}{2}\)
Answer:
Qty A = Qty B = \(\frac{x}{2}\)
C
\(\frac{x(5−√17)(√17+5)}{√256} = \frac{(5x−x√17)(√17+5)}{√256} = \frac{(5x√17 + 25 x - 17 x - 5x√17)}{√256} = \frac{8x}{√256} = \frac{8x}{16} = \frac{x}{2}\)
Quantity B:
Area of ABC = ( y * [x/y] )/2 = \(\frac{x}{2}\)
Answer:
Qty A = Qty B = \(\frac{x}{2}\)
C
gmatclubot
ABC is a right triangle with legs of length x/y [#permalink]
28 Dec 2021, 11:33
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