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The average of a set of five values is 12. If one number is deleted, t
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07 Jan 2022, 02:53
07 Jan 2022, 02:53
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The average of a set of five values is 12. If one number is deleted, the average of the set is decreased by 0.6. What is the value of the deleted number?
(A) 14.2
(B) 14.4
(C) 16.2
(D) 19.6
(E) 20.2
Kudos for the right answer and explanation
See more at this link GRE Tips and Tricks - UPDATED 11/20/2021
(A) 14.2
(B) 14.4
(C) 16.2
(D) 19.6
(E) 20.2
Kudos for the right answer and explanation
See more at this link GRE Tips and Tricks - UPDATED 11/20/2021
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Re: The average of a set of five values is 12. If one number is deleted, t
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07 Jan 2022, 06:00
07 Jan 2022, 06:00
1
Carcass wrote:
The average of a set of five values is 12. If one number is deleted, the average of the set is decreased by 0.6. What is the value of the deleted number?
(A) 14.2
(B) 14.4
(C) 16.2
(D) 19.6
(E) 20.2
Kudos for the right answer and explanation
See more at this link GRE Tips and Tricks - UPDATED 11/20/2021
(A) 14.2
(B) 14.4
(C) 16.2
(D) 19.6
(E) 20.2
Kudos for the right answer and explanation
See more at this link GRE Tips and Tricks - UPDATED 11/20/2021
Let a, b, c, d and e be the 5 numbers
The average of a set of five values is 12.
We can write: \(\frac{a+b+c+d+e}{5} = 12\)
Multiply both sides by 5 to get: \(a+b+c+d+e=60\)
If one number is deleted, the average of the set is decreased by 0.6
In other words, if e is deleted, the average of the 4 remaining numbers is 11.4
We can write: \(\frac{a+b+c+d}{4} = 11.4\)
Multiply both sides by 4 to get: \(a+b+c+d=45.6\)
What is the value of the deleted number?
We have:
\(a+b+c+d+e=60\)
\(a+b+c+d=45.6\)
Subtract the bottom equation from the top equation to get: \(e = 14.4\)
Answer: B
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Re: The average of a set of five values is 12. If one number is deleted, t
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07 Jan 2022, 06:19
07 Jan 2022, 06:19
1
The average of a set of five values is 12
Sum = Average * Number of Values
=> Sum of these 5 numbers, \(S_5\) = 12*5 = 60 ...(1)
If one number is deleted, the average of the set is decreased by 0.6
Let the deleted number be x and sum of remaining 4 numbers is \(S_4\)
=> \(S_4 \)= (Old Average - 0.6)*4 = (12-0.6)*4 = 45.6
From (1)
\(S_5\) = 60
\(S_5 \)= \(S_4\) + x = 45.6 + x = 60
=> x = 60 - 45.6 = 14.4
So, Answer will be B
Hope it helps!
Watch the following video to Learn the Basics of Statistics
Sum = Average * Number of Values
=> Sum of these 5 numbers, \(S_5\) = 12*5 = 60 ...(1)
If one number is deleted, the average of the set is decreased by 0.6
Let the deleted number be x and sum of remaining 4 numbers is \(S_4\)
=> \(S_4 \)= (Old Average - 0.6)*4 = (12-0.6)*4 = 45.6
From (1)
\(S_5\) = 60
\(S_5 \)= \(S_4\) + x = 45.6 + x = 60
=> x = 60 - 45.6 = 14.4
So, Answer will be B
Hope it helps!
Watch the following video to Learn the Basics of Statistics
