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The average (arithmetic mean) of 6 numbers is 8.5. When one number is
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09 Aug 2021, 15:29
09 Aug 2021, 15:29
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The average (arithmetic mean) of 6 numbers is 8.5. When one number is discarded, the average of the remaining numbers becomes 7.2. What is the discarded number?
(A) 7.8
(B) 9.8
(C) 10.0
(D) 12.4
(E) 15.0
(A) 7.8
(B) 9.8
(C) 10.0
(D) 12.4
(E) 15.0
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Re: The average (arithmetic mean) of 6 numbers is 8.5. When one number is
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09 Aug 2021, 15:46
09 Aug 2021, 15:46
1
Carcass wrote:
The average (arithmetic mean) of 6 numbers is 8.5. When one number is discarded, the average of the remaining numbers becomes 7.2. What is the discarded number?
(A) 7.8
(B) 9.8
(C) 10.0
(D) 12.4
(E) 15.0
(A) 7.8
(B) 9.8
(C) 10.0
(D) 12.4
(E) 15.0
Simplify: 19 + m + n = 45
Subtract 19 from both sides to get: m + n = 26
What is the average of m + 4 and n – 2 ?
We get: average = [(m + 4) + (n - 2)]/2
Simplify: average = (m + n + 2)/2
Replace m + n to get: average = (26 + 2)/2
Simplify: average = (28)/2 = 14
Answer: C
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Re: The average (arithmetic mean) of 6 numbers is 8.5. When one number is
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23 Jan 2022, 17:49
23 Jan 2022, 17:49
1
(Average)(# of terms) = Sum of all the terms
(8.5)(6) = 51
When one number is discarded, the average of the remaining numbers becomes 7.2:
(Average)(# of terms) = Sum of all the integers
(7.2)(5) = 36
51 - 36 = 15
Answer E
(8.5)(6) = 51
When one number is discarded, the average of the remaining numbers becomes 7.2:
(Average)(# of terms) = Sum of all the integers
(7.2)(5) = 36
51 - 36 = 15
Answer E
