Carcass wrote:
How many even numbers of 4 digits can be formed using digits 0, 1, 2, 3, 4, 5 and 6 ? (Repetition is not allowed)
A. 420
B. 480
C. 828
D. 840
E. 864
Since a 4-digit number cannot begin with 0, we must consider two cases:
- 4-digit numbers with 0 in the units position
- 4-digit numbers with 2, 4 or 6 in the units position
4-digit numbers with 0 in the units positionWe can choose a digit for the units position in
1 way (since the units digit must be 0)
We can choose a digit for the tens position in
6 ways (since are 6 digits remaining to choose from)
We can choose a digit for the hundreds position in
5 ways (we can choose any of the 5 remaining digits)
We can choose a digit for the thousands position in
4 ways (we can choose any of the 4 remaining digits)
By the Fundamental Counting Principle (FCP), we can complete all 4 steps (and thus create a 5-digit number) in
(1)(6)(5)(4) ways (=
120 ways)
4-digit numbers with 2, 4 or 6 in the units position We can choose a digit for the units position in
3 ways (since the units digit can be 2, 4 or 6)
We can choose a digit for the THOUSANDS position in
5 ways (since are 5 NON-ZERO digits remaining to choose from)
We can choose a digit for the tens position in
5 ways (we can choose any of the 5 remaining digits)
We can choose a digit for the hundreds position in
4 ways
By the Fundamental Counting Principle (FCP), we can complete all 4 steps (and thus create a 5-digit number) in
(3)(5)(5)(4) ways (=
300 ways)
So, the total number of four digit numbers possible =
120 +
300 =
420Answer: A