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Re: Two integers x and y are in the ratio of 5:6 [#permalink]
Why is E not a correct answer

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Re: Two integers x and y are in the ratio of 5:6 [#permalink]
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Harsh2910 wrote:
Why is E not a correct answer

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E is true if and only if X and Y are only positive.
Consider:
x=-5, y=-6 (x>y)
but
x=5, y=6 is also valid (y>x)
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Re: Two integers x and y are in the ratio of 5:6 [#permalink]
Sumukh19 wrote:
YashZ wrote:
Why A is not one of the correct answer choices?


Let's assume that \(X=5a\) and \(Y=6a\) as they are in the ratio of 5:6

Therefore,
\(X+Y=5a+6a=11a\)

Here, it seems like 11 is the highest prime factor of \(X+Y\) but what if \(a\) is another prime number greater than 11, in that case \(a\) will the highest prime factor of \(X+Y\).

For example
\(X=65\)
\(Y=78\)

Then, \(X+Y=143\)
Here, the highest prime factor will be 13.

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But it is written "A. 11 can be the highest prime factor of X+Y" not 11 must be...
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Re: Two integers x and y are in the ratio of 5:6 [#permalink]
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Re: Two integers x and y are in the ratio of 5:6 [#permalink]
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