GreenlightTestPrep wrote:
Joe regularly drives the 400 miles from A-ville to B-town at the same constant speed of r miles per hour. If Joe drives 30 mph faster than usual, it takes him 3 fewer hours to complete the trip. What is the value of r?
Let's start with a
word equation.
In this question, we're comparing trips when Joe drives at his REGULAR speed with a HYPOTHETICAL trip at a faster speed
The question tells us that the HYPOTHETICAL trip takes 3 fewer hours than the REGULAR trip.
So, we can write:
(time to complete REGULAR trip) - (time to complete HYPOTHETICAL trip) = 3 hoursIf Joe's REGULAR speed is
r miles per hour, then his HYPOTHETICAL speed must be
r + 30time = distance/speedSo we can substitute values into our word equation to get:
400/r - 400/(r + 30) = 3Multiply both sides of the equation by r to get:
400 - 400r/(r+30) = 3rMultiply both sides of the equation by r + 30 to get:
400(r + 30) - 400r = 3r(r+30)Expand both sides:
400r + 12,000 - 400r = 3r² +90r Simplify the left side:
12,000 = 3r² +90r Subtract 12,000 from both sides:
0 = 3r² +90r - 12,000Divide both sides by 3 to get:
0 = r² +30r - 4,000Factor:
0 = (r + 80)(r - 50)So, EITHER
r = -80 OR
r = 50Since Bob's speed can't be negative, the correct answer is r = 50
Answer: 50