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Which of the following expressions is equivalent to
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08 Feb 2022, 06:00
08 Feb 2022, 06:00
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Which of the following expressions is equivalent to \(\frac{6}{4+\sqrt{7}}\) ?
A \(\frac{2(4-\sqrt{7})}{3}\)
B \(\frac{6(4+\sqrt{7})}{23}\)
C \(\frac{(4-\sqrt{7})}{3}\)
D \(\frac{6(4-\sqrt{7})}{23}\)
A \(\frac{2(4-\sqrt{7})}{3}\)
B \(\frac{6(4+\sqrt{7})}{23}\)
C \(\frac{(4-\sqrt{7})}{3}\)
D \(\frac{6(4-\sqrt{7})}{23}\)
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Which of the following expressions is equivalent to
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11 Feb 2022, 06:54
11 Feb 2022, 06:54
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Carcass wrote:
Which of the following expressions is equivalent to \(\frac{6}{4+\sqrt{7}}\) ?
A \(\frac{2(4-\sqrt{7})}{3}\)
B \(\frac{6(4+\sqrt{7})}{23}\)
C \(\frac{(4-\sqrt{7})}{3}\)
D \(\frac{6(4-\sqrt{7})}{23}\)
A \(\frac{2(4-\sqrt{7})}{3}\)
B \(\frac{6(4+\sqrt{7})}{23}\)
C \(\frac{(4-\sqrt{7})}{3}\)
D \(\frac{6(4-\sqrt{7})}{23}\)
To rationalize the denominator we must multiply numerator and denominator by \(4-\sqrt{7}\), which is the compliment of \(4+\sqrt{7}\)
We get: \(\frac{6(4-\sqrt{7})}{(4+\sqrt{7})(4-\sqrt{7})}\)
Expand and simplify the denominator: \(\frac{6(4-\sqrt{7})}{9}\)
Simplify by dividing numerator and denominator by \(3\) to get: \(\frac{2(4-\sqrt{7})}{3}\)
Answer: A
Re: Which of the following expressions is equivalent to
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15 Feb 2023, 02:38
15 Feb 2023, 02:38
Hi Brent GreenlightTestPrep
In this stage, 6(4−√7)/9, when multiply 6 into get (24-6√7)/9
simplify to get (8-6√7)/3
What went wrong here? Is the multiplication here not allowed?
In this stage, 6(4−√7)/9, when multiply 6 into get (24-6√7)/9
simplify to get (8-6√7)/3
What went wrong here? Is the multiplication here not allowed?
