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If two lists of 4 consecutive even integers are separated by 2 even nu
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09 Feb 2022, 04:00
09 Feb 2022, 04:00
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If two lists of 4 consecutive even integers are separated by 2 even numbers, the sum of the 4 integers on one list is how much greater than the sum of the other?
(A) 24
(B) 36
(C) 48
(D) 60
(E) Cannot be determined
(A) 24
(B) 36
(C) 48
(D) 60
(E) Cannot be determined
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Re: If two lists of 4 consecutive even integers are separated by 2 even nu
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09 Feb 2022, 06:23
09 Feb 2022, 06:23
1
Carcass wrote:
If two lists of 4 consecutive even integers are separated by 2 even numbers, the sum of the 4 integers on one list is how much greater than the sum of the other?
(A) 24
(B) 36
(C) 48
(D) 60
(E) Cannot be determined
(A) 24
(B) 36
(C) 48
(D) 60
(E) Cannot be determined
Let x = the smallest even integer in the set with the four smaller even integers.
So, x + 2 = the next even integer in the set with the four smaller even integers.
x + 4 = the next even integer in the set with the four smaller even integers.
x + 6 = the next even integer in the set with the four smaller even integers.
This set of four integers is separated from the other set of integers by two even numbers, which means:
x + 8 = in the first even number separating the two sets
x + 10 = in the other even number separating the two sets
And now comes the other set of four integers....
x + 12 = the first even integer in the set with the four larger even integers.
So, x + 14 = the next even integer in the set with the four larger even integers.
x + 16 = the next even integer in the set with the four larger even integers.
x + 18 = the next even integer in the set with the four larger even integers.
Sum of the four smaller even numbers = x + (x + 2) + (x + 4) + (x + 6) = 4x + 12
Sum of the four larger even numbers = (x + 12) + (x + 14) + (x + 16) + (x + 18) = 4x + 60
The DIFFERENCE between the two sums = (4x + 60) - (4x + 12) = 48
Answer: C
General Discussion
Re: If two lists of 4 consecutive even integers are separated by 2 even nu
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05 Jun 2024, 02:51
05 Jun 2024, 02:51
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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