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0 < x < 1
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15 Feb 2022, 23:26
15 Feb 2022, 23:26
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\(0 < x < 1\)
A) The quantity in Column A is greater.
B) The quantity in Column B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(\frac{1}{x}\) |
\(\frac{ 1}{x^2} \) |
A) The quantity in Column A is greater.
B) The quantity in Column B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Re: 0 < x < 1
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16 Feb 2022, 06:35
16 Feb 2022, 06:35
1
Carcass wrote:
\(0 < x < 1\)
A) The quantity in Column A is greater.
B) The quantity in Column B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(\frac{1}{x}\) |
\(\frac{ 1}{x^2} \) |
A) The quantity in Column A is greater.
B) The quantity in Column B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
We can solve this question using matching operations (my favorite Quantitative Comparison strategy)
Given:
Quantity A: \(\frac{1}{x}\)
Quantity B: \(\frac{ 1}{x^2} \)
Since we can be certain that \(x^2\) is POSITIVE, we can multiply both quantities by \(x^2\) to get:
Quantity A: \(x\)
Quantity B: \(1 \)
Since we're told \(0 < x < 1\), we can be certain that Quantity B is greater
Answer: B
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Re: 0 < x < 1
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16 Feb 2022, 10:31
16 Feb 2022, 10:31
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1
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Carcass wrote:
\(0 < x < 1\)
A) The quantity in Column A is greater.
B) The quantity in Column B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(\frac{1}{x}\) |
\(\frac{ 1}{x^2} \) |
A) The quantity in Column A is greater.
B) The quantity in Column B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Lets test few no.
Case 1: x =1/2 A =2 & B = 4 --- A<B
Case 2: x= 1/10 A =10 & B = 100 ----A<B
Imo ans is B
