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In a garden, there are three blue flowers, three red flowers, three gr
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12 Oct 2021, 09:53
12 Oct 2021, 09:53
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In a garden, there are three blue flowers, three red flowers, three green flowers, and three pink flowers. What is the probability that a florist will choose three flowers of the same color when randomly picking three flowers?
A. 11/10
B. 1/55
C. 31/10
D. 3/55
E. 1/16
A. 11/10
B. 1/55
C. 31/10
D. 3/55
E. 1/16
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Re: In a garden, there are three blue flowers, three red flowers, three gr
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12 Oct 2021, 10:00
12 Oct 2021, 10:00
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Carcass wrote:
In a garden, there are three blue flowers, three red flowers, three green flowers, and three pink flowers. What is the probability that a florist will choose three flowers of the same color when randomly picking three flowers?
A. 11/10
B. 1/55
C. 31/10
D. 3/55
E. 1/16
A. 11/10
B. 1/55
C. 31/10
D. 3/55
E. 1/16
P(all the same color) = P(1st flower is ANY color AND 2nd flower is same as first AND 3rd flower is also the same color)
= P(1st flower is ANY color) x P(2nd flower is same as 1st) AND P(3rd flower is the same color)
= 1 x 2/11 x 1/10
= 1/55
Answer: B
Re: In a garden, there are three blue flowers, three red flowers, three gr
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20 Feb 2022, 08:53
20 Feb 2022, 08:53
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I did it as follows.
Total number of flowers 12
The total group of 3 flowers is 4. (3 blue flowers, 3 red flowers, 3 green flowers, and 3 pink flowers)
Assuming the florist will pick is Blue (It can be any color. I like blue
)
Therefore,
The probability of getting 1st blue is 3/12 = 1/4
The probability of getting 2nd blue is 2/11
The probability of getting 3rd blue is 1/10
Multiplying all of them together 1/4 X 2/11 X 1/10 = 1/220
Now, as mentioned earlier, it can be any color group. And we know there are 4 total groups of 3 same colored flowers. The probability for each color will be the same. So we can multiply the entire fraction by 4. So the result is (1/220) X 4 = 1/55. (Option B).
A bit time consuming but I did it this way.
Total number of flowers 12
The total group of 3 flowers is 4. (3 blue flowers, 3 red flowers, 3 green flowers, and 3 pink flowers)
Assuming the florist will pick is Blue (It can be any color. I like blue
)Therefore,
The probability of getting 1st blue is 3/12 = 1/4
The probability of getting 2nd blue is 2/11
The probability of getting 3rd blue is 1/10
Multiplying all of them together 1/4 X 2/11 X 1/10 = 1/220
Now, as mentioned earlier, it can be any color group. And we know there are 4 total groups of 3 same colored flowers. The probability for each color will be the same. So we can multiply the entire fraction by 4. So the result is (1/220) X 4 = 1/55. (Option B).
A bit time consuming but I did it this way.
