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Sid intended to type a seven-digit number, but the two 3's h
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19 Nov 2019, 11:15
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75% (01:23) correct
25% (01:28) wrong based on 24 sessions
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Sid intended to type a seven-digit number, but the two 3's he meant to type did not appear. What appeared instead was the five-digit number 52115. How many different seven-digit numbers could Sid have meant to type?
Sid intended to type a seven-digit number, but the two 3's h
[#permalink]
20 Jul 2020, 06:40
1
huda wrote:
Sid intended to type a seven-digit number, but the two 3's he meant to type did not appear. What appeared instead was the five-digit number 52115. How many different seven-digit numbers could Sid have meant to type?
A. 10 B. 16 C. 21 D. 24 E. 27
There are two possible cases to examine here: case i) the two 3's are adjacent case ii) the two 3's are NOT adjacent
case i) the two 3's are adjacent Let's add spaces to where the two 3's can appear: _5_2_1_1_5_ There are 6 possible spaces where the two adjacent 3's can appear So there are 6 possible ways in which the two adjacent 3's can appear
case ii) the two 3's are NOT adjacent Let's add spaces to where the two 3's can appear: _5_2_1_1_5_ There are 6 possible spaces where the two non-adjacent 3's can appear We must choose 2 different spaces Since the order in which we choose the two spaces does not matter, we can use combinations. We can choose 2 of the 6 spaces in 6C2 ways 6C2 = (6)(5)/(2)(1) = 15 So there are 15 possible ways in which two non-adjacent 3's can appear
Aside: The video below explains how to quickly calculate combinations (like 6C2) in your head
Re: Sid intended to type a seven-digit number, but the two 3's h
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20 Feb 2022, 13:20
Hello from the GRE Prep Club BumpBot!
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
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Re: Sid intended to type a seven-digit number, but the two 3's h [#permalink]