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Suppose 3.5x + 1.5y + 1 = –0.5y – 2.5x . If y2 = 4, what is the value
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25 Feb 2022, 05:00
25 Feb 2022, 05:00
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If \(3.5x + 1.5y + 1 = –0.5y – 2.5x\), and \(y^2 = 4\), what is the value of \(x\)?
Indicate all such values.
A. \(-2\)
B. \(-\frac{5}{6}\)
C. \(-\frac{1}{2}\)
D. \(\frac{1}{2}\)
E. \(\frac{5}{6}\)
F. \(2\)
Indicate all such values.
A. \(-2\)
B. \(-\frac{5}{6}\)
C. \(-\frac{1}{2}\)
D. \(\frac{1}{2}\)
E. \(\frac{5}{6}\)
F. \(2\)
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Re: Suppose 3.5x + 1.5y + 1 = –0.5y – 2.5x . If y2 = 4, what is the value
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25 Feb 2022, 06:32
25 Feb 2022, 06:32
2
Carcass wrote:
If \(3.5x + 1.5y + 1 = –0.5y – 2.5x\), and \(y^2 = 4\), what is the value of \(x\)?
Indicate all such values.
A. \(-2\)
B. \(-\frac{5}{6}\)
C. \(-\frac{1}{2}\)
D. \(\frac{1}{2}\)
E. \(\frac{5}{6}\)
F. \(2\)
Indicate all such values.
A. \(-2\)
B. \(-\frac{5}{6}\)
C. \(-\frac{1}{2}\)
D. \(\frac{1}{2}\)
E. \(\frac{5}{6}\)
F. \(2\)
Take: \(3.5x + 1.5y + 1 = –0.5y – 2.5x\)
Add \(0.5y\) to both sides and add \(2.5x\) to both sides to get: \(6x + 2y + 1 = 0\)
If \(y^2 = 4\), then EITHER \(y = 2\) OR \(y = -2\).
Let's examine each case...
If \(y = 2\), then our equation becomes: \(6x + 2(2) + 1 = 0\)
Simplify: \(6x + 5 = 0\)
Subtract \(5\) from both sides: \(6x = -5\)
Divide both sides by \(6\) to get: \(x = -\frac{5}{6}\)
If \(y = -2\), then our equation becomes: \(6x + 2(-2) + 1 = 0\)
Simplify: \(6x - 3 = 0\)
Add \(3\) to both sides: \(6x = 3\)
Divide both sides by \(6\) to get: \(x = \frac{3}{6}= \frac{1}{2}\)
Answer: B, D
Re: Suppose 3.5x + 1.5y + 1 = 0.5y 2.5x . If y2 = 4, what is the value
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01 Jun 2023, 16:25
01 Jun 2023, 16:25
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Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
