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a>b>c>d>e>f>g>h>i>j>k
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02 Mar 2022, 09:55
02 Mar 2022, 09:55
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76% (00:42) correct
23% (01:01) wrong based on 21 sessions
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\(a>b>c>d>e>f>g>h>i>j>k\)
A Quantity A is greater.
B Quantity B is greater.
C The two quantities are equal.
D The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(e\) |
\(\)\(\frac{a + b + c + d + e + f + g + h + i + j + k}{11}\) |
A Quantity A is greater.
B Quantity B is greater.
C The two quantities are equal.
D The relationship cannot be determined from the information given.
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a>b>c>d>e>f>g>h>i>j>k
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02 Mar 2022, 10:42
02 Mar 2022, 10:42
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schrodinger wrote:
\(a>b>c>d>e>f>g>h>i>j>k\)
A Quantity A is greater.
B Quantity B is greater.
C The two quantities are equal.
D The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(e\) |
\(\)\(\frac{a + b + c + d + e + f + g + h + i + j + k}{11}\) |
A Quantity A is greater.
B Quantity B is greater.
C The two quantities are equal.
D The relationship cannot be determined from the information given.
Note: \(\frac{a + b + c + d + e + f + g + h + i + j + k}{11}\) is the AVERAGE of the values from a to k
There are many possible scenarios that satisfy the given information:
case a: The values for k, j, i, h, g, f, e, d, c, b, a are 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 1,000,000,000,000,000,000 respectively.
So, we have:
Quantity A: e = 7
Quantity B: The average is much bigger than greater than 7
So, Quantity B is greater
case b: The values for k, j, i, h, g, f, e, d, c, b, a are -1,000,000,000,000,000,000, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, respectively.
So, we have:
Quantity A: e = 6
Quantity B: The average is much smaller than greater than 6
So, Quantity A is greater
Answer: D
General Discussion
Re: a>b>c>d>e>f>g>h>i>j>k
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02 Mar 2022, 10:35
02 Mar 2022, 10:35
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Expert Reply
We are given with the set of numbers in the descending order. But the values are not known. Hence, their average could either be greater than, less than, or equal to e.
For better and a quick understanding, let's consider a small set 10 > 9 >8 > x > 4 >3 > 2. If x is 7, the average will be 6.14. If x= 5, the average will be 5.85. Hence, the answer is D.
For better and a quick understanding, let's consider a small set 10 > 9 >8 > x > 4 >3 > 2. If x is 7, the average will be 6.14. If x= 5, the average will be 5.85. Hence, the answer is D.
