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Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
3^x/3^y= (3^x)(3^y)
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07 Mar 2022, 04:00
07 Mar 2022, 04:00
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\(\frac{3^x}{3^y} = (3^x)(3^y)\)
A) The quantity in Column A is greater.
B) The quantity in Column B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(y\) |
\(0\) |
A) The quantity in Column A is greater.
B) The quantity in Column B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Re: 3^x/3^y= (3^x)(3^y)
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07 Mar 2022, 10:43
07 Mar 2022, 10:43
GreenlightTestPrep wrote:
\(\frac{3^x}{3^y} = (3^x)(3^y)\)
A) The quantity in Column A is greater.
B) The quantity in Column B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
\(y\) |
\(0\) |
A) The quantity in Column A is greater.
B) The quantity in Column B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
Above equation can be simplified as 3^x-y = 3^x+y -----> x-y = x+y, this lead to y = 0 hence ans is C
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: 3^x/3^y= (3^x)(3^y)
[#permalink]
10 Mar 2022, 06:20
10 Mar 2022, 06:20
1
GreenlightTestPrep wrote:
\(\frac{3^x}{3^y} = (3^x)(3^y)\)
Quantity A |
Quantity B |
\(y\) |
\(0\) |
Given: \(\frac{3^x}{3^y} = (3^x)(3^y)\)
Apply the Quotient Law and the Product Law to simplify both sides: \(3^{x-y} = 3^{x+y}\)
Since the bases are the same, the exponents must be equal: \(x-y = x+y\)
Subtract \(x\) from both sides of the equation: \(-y = y\)
Add \(y\) to both sides: \(0 = 2y\)
Solve: \(y = 0\) to get:
QUANTITY A: \(y = 0\)
QUANTITY B: \(0\)
Answer: C
