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f(x) = 5x^2-9.2x^4/25.7+x^6

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Carcass
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f(x) = 5x^2-9.2x^4/25.7+x^6 [#permalink] New post   29 Mar 2022, 02:00
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\(f(x) = \frac{5x^2-9.2x^4}{25.7+x^6}\)


Quantity A
Quantity B
\(f(2.38)\)
\(f(-2.38)\)



A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given


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C
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AkkuJi
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Re: f(x) = 5x^2-9.2x^4/25.7+x^6 [#permalink] New post   29 Mar 2022, 10:53
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Carcass wrote:
\(f(x) = \frac{5x^2-9.2x^4}{25.7+x^6}\)


Quantity A
Quantity B
\(f(2.38)\)
\(f(-2.38)\)



A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given





Power of x is even, so it doesn't matter if x is -ve or +ve, result will be same, hence option C is ans
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BrushMyQuant
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Re: f(x) = 5x^2-9.2x^4/25.7+x^6 [#permalink] New post   25 Aug 2022, 10:12
1
Given that \(f(x) = \frac{5x^2-9.2x^4}{25.7+x^6}\) and we need to compare Quantity A ( f(2.38) ) and Quantity B ( f(-2.38) )

Now, f(x) has only even powers of x in numerator and denominator. So if we same value of x but with different sign then f(x) is going to give the same value in both the cases

And Quantity A = f(2.8) and Quantity B = f(-2.8)

=> Quantity A = Quantity B

So, Answer will be C
Hope it helps!

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Re: f(x) = 5x^2-9.2x^4/25.7+x^6 [#permalink]
25 Aug 2022, 10:12
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