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O is the center of the circle. A is the midpoint of OB = BC = 8. If a
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01 Apr 2022, 02:00
01 Apr 2022, 02:00
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88% (02:30) correct
11% (01:30) wrong based on 9 sessions
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O is the center of the circle. A is the midpoint of \\(overline{OB}\) \(OB= BC = 8.\) If a point is randomly chosen from the square, what is the probability it will be in both the circle and the triangle?
A. \(\frac{1}{25}\)
B. \(\frac{\pi}{25}\)
C. \(\frac{4}{25}\)
D. \(\frac{\pi}{100}\)
E. \(\frac{\pi}{200}\)
Part of the project: GRE Quantitative Reasoning Daily Challenge - (2022) EDITION
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GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
GRE - Math Book
Re: O is the center of the circle. A is the midpoint of OB = BC = 8. If a
[#permalink]
01 Apr 2022, 11:02
01 Apr 2022, 11:02
1
Since A is midpoint of OB and OB is equal to 8, radius of circle is equal to 4 and also since it's an isosceles triangle (since OB = BC)
angle AOC is equal to 45
Area of sector = 45/360 * pi * 16
Area of square = 20 * 20
Probability = Area of sector/Area of square
On simplifying we get pi/200, hence option E is ans
angle AOC is equal to 45
Area of sector = 45/360 * pi * 16
Area of square = 20 * 20
Probability = Area of sector/Area of square
On simplifying we get pi/200, hence option E is ans
gmatclubot
Re: O is the center of the circle. A is the midpoint of OB = BC = 8. If a [#permalink]
01 Apr 2022, 11:02
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