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At a certain university, the ratio of the number of teaching assistant

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GeminiHeat
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At a certain university, the ratio of the number of teaching assistant [#permalink] New post   04 Apr 2022, 00:42
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At a certain university, the ratio of the number of teaching assistants to the number of students in any course must always be greater than 3:80. At this university , what is the maximum number of students possible in a course that has 5 teaching assistants?

A. 130
B. 131
C. 132
D. 133
E. 134
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Re: At a certain university, the ratio of the number of teaching assistant [#permalink] New post   04 Apr 2022, 19:25
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A:S= 3:80=5:x
3x=400 [product of mean =product of extreme]
X=400/3
=133.33
=133 [Now for ratio to be greater than 3/80 reduce the denominator. So just rounded it to lowest integer as number of student can't be in decimal. The new ratio is 5/133, which is less than 3/80 ,SO 133 is the maximum number of students possible.]
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Re: At a certain university, the ratio of the number of teaching assistant [#permalink] New post   07 Apr 2023, 06:48
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GeminiHeat wrote:
At a certain university, the ratio of the number of teaching assistants to the number of students in any course must always be greater than 3:80. At this university , what is the maximum number of students possible in a course that has 5 teaching assistants?

A. 130
B. 131
C. 132
D. 133
E. 134


We are given that the ratio of the number of teaching assistants to the number of students in any course must always be greater than 3:80, and we need to determine the maximum number of students possible in a course that has 5 teaching assistants. Let’s use the following formula, in which t = 5 = the number of teaching assistants and s = the number of students.

t/s> 3/80

5/s > 3/80

400 > 3s

400/3 > s

133.33 > s

Since s must be a whole number, the largest possible value of s is 133.

Answer: D
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Re: At a certain university, the ratio of the number of teaching assistant [#permalink]
07 Apr 2023, 06:48
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