Carcass wrote:
From a deck of 52 cards, 2 cards are randomly drawn. What is the probability that the first card is a 10?
(A) 1/26
(B) 1/17
(C) 1/13
(D) 12/51
(E) 1/4
Total number of cards = 52
Number of 10's = 4
Prob. of picking a 10 as the first card = \(\frac{4}{52} = \frac{1}{13}\)
Now, it doesn't matter what card is picked as the second card becuase we already have a 10 as a first card. So, Prob. of picking any card as the second card = 1
Therefore, required Prob. = \(\frac{1}{13}\)
Hence, option C