Last visit was: 25 Nov 2024, 14:06 It is currently 25 Nov 2024, 14:06

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
GRE Prep Club Team Member
Joined: 20 Feb 2017
Posts: 2508
Own Kudos [?]: 3626 [2]
Given Kudos: 1053
GPA: 3.39
Send PM
avatar
Intern
Intern
Joined: 13 Apr 2022
Posts: 3
Own Kudos [?]: 0 [0]
Given Kudos: 1
Send PM
Verbal Expert
Joined: 18 Apr 2015
Posts: 30024
Own Kudos [?]: 36397 [0]
Given Kudos: 25929
Send PM
Verbal Expert
Joined: 18 Apr 2015
Posts: 30024
Own Kudos [?]: 36397 [1]
Given Kudos: 25929
Send PM
Re: In the figure above, all the marked angles are some multiple of x [#permalink]
1
Expert Reply
Image

Note that two intersecting lines make 4 angles around the point of intersection such that vertically opposite angles are equal. Can one of the angles be 320 degrees? The other needs to be 320 degrees too. If a is 320, c needs to be 320 too!


Image


Hence, the options (C), (D) and (E) are not possible.

Now it is just about looking for a pair of supplementary angles.
If x = 10, 2x + 16x = 18x = 180
So 2x = 20 degrees and the angle supplementary to 16x would be 20 degrees too making these two lines parallel.

Answer (B)
avatar
Intern
Intern
Joined: 13 Apr 2022
Posts: 3
Own Kudos [?]: 0 [0]
Given Kudos: 1
Send PM
Re: In the figure above, all the marked angles are some multiple of x [#permalink]
Carcass wrote:
for lines with angles 4x and 8x to be parallel => 4x + 8x = 12x = 180, x = 15
for lines with angles 2x and 16x to be parallel => 2x + 16x = 18x = 180, x = 10 (minimum so far)
tried with x = 8, found none to be parallel.

So answer (B)


Is question asking for the minimum value of x?
Verbal Expert
Joined: 18 Apr 2015
Posts: 30024
Own Kudos [?]: 36397 [0]
Given Kudos: 25929
Send PM
Re: In the figure above, all the marked angles are some multiple of x [#permalink]
Expert Reply
shvndry wrote:
Carcass wrote:
for lines with angles 4x and 8x to be parallel => 4x + 8x = 12x = 180, x = 15
for lines with angles 2x and 16x to be parallel => 2x + 16x = 18x = 180, x = 10 (minimum so far)
tried with x = 8, found none to be parallel.

So answer (B)


Is question asking for the minimum value of x?



No basically we need to figure out WHEN x has a certain value to have lines parallel

The minimum value is x=10 but the question is different when asking

Quote:
[What is the minimum possible population that the least populated district could have?


Hope this helps
Retired Moderator
Joined: 12 Feb 2022
Posts: 266
Own Kudos [?]: 228 [1]
Given Kudos: 68
Location: India
Concentration: Entrepreneurship, General Management
GPA: 3.5
Send PM
Re: In the figure above, all the marked angles are some multiple of x [#permalink]
1
Lets try with x and 2x ---> x +2x = 180 for line to be ||-----> 3x = 180 ---> x = 60, so options 10, 15, 20 are okay, with 10 being the 1st in the queue to satisfy the condition.

Ans is option B
Prep Club for GRE Bot
Re: In the figure above, all the marked angles are some multiple of x [#permalink]
Moderators:
GRE Instructor
84 posts
GRE Forum Moderator
37 posts
Moderator
1111 posts
GRE Instructor
234 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne