Carcass wrote:
If the hypotenuse of an isosceles right triangle has length of 8, then the area of the triangle is
A. 4
B. 4√2
C. 8
D. 8√2
E. 16
Let's sketch the given information.

Let
x = the length of each of the two equal sides

From here, we can apply the Pythagorean theorem to write: x² + x² = 8²
Simplify: 2x² = 64
Divide both sides of the equation by 2 to get: x² = 32
This means
x = √32 [you'll see why I didn't bother simplifying √32 shortly]So we have the following:
Triangle area = (base)(height)/2 = (
√32)(
√32)/2 = 32/2 = 16
Answer: E