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Carl drove from his home to the beach at an average speed of 80 kilome
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29 Apr 2022, 01:00
29 Apr 2022, 01:00
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Carl drove from his home to the beach at an average speed of 80 kilometers per hour and returned home by the same route at an average speed of 70 kilometers per hour. If the trip home took 1/2 hour longer than the trip to the beach, how many kilometers did Carl drive each way?
Show: ::
280
Part of the project: GRE Quantitative Reasoning Daily Challenge - (2022) EDITION
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
GRE - Math Book
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Re: Carl drove from his home to the beach at an average speed of 80 kilome
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29 Apr 2022, 06:37
29 Apr 2022, 06:37
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Carcass wrote:
Carl drove from his home to the beach at an average speed of 80 kilometers per hour and returned home by the same route at an average speed of 70 kilometers per hour. If the trip home took 1/2 hour longer than the trip to the beach, how many kilometers did Carl drive each way?
Show: ::
280
Since the travel time going home was 0.5 hours longer than the travel time going to the beach, we can start with the following word equation:
(travel time going home) - (travel time to beach) = 0.5
Let d = the distance from home to beach
Since time = distance/rate, we can plug in the given values to get: (d/70) - (d/80) = 0.5
To eliminate the fractions, multiply both sides of the equation by 560 to get: 8d - 7d = 280
Simplify: d = 280
Answer: 280
Re: Carl drove from his home to the beach at an average speed of 80 kilome
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08 Jan 2023, 08:15
08 Jan 2023, 08:15
1
D=RT
D=R1T1=R2T2
R1=80
R2=70
T2=T1+0.5
Therefore,
D=80T1=70(T1+0.5)
80T1-70T1=35
T1=3.5
D=R1T1
D=3.5*80
D=280
D=R1T1=R2T2
R1=80
R2=70
T2=T1+0.5
Therefore,
D=80T1=70(T1+0.5)
80T1-70T1=35
T1=3.5
D=R1T1
D=3.5*80
D=280
